Daily Scribe

Daily Scribe for 2/2/10

On Tuesday, we finished up problem 1.3 in Comparing and Scaling. 1.3 is about comparing the circumference, height, and spread/diameter of different kinds of trees. Here are some of the problems that we got to go over in class:

A.1. It takes about 1.5 redwood spreads to equal the spread of the white oak.
2. Yes, Kenning is correct because 120 (white oak spread): 80 (coast redwood spread) is equal to 3:2.
3. Yes, Mary is correct because 321 (height of coast redwood)-275 (height of giant sequoia)= 46.
4. It takes about 2 giant sequoias spreads to equal the spread of the swamp chestnut oak.
5. Jaime is correct because half of 216 is 108, and that is more than 107.
6. Yes, Len is correct.

B. The ratio of the height of the coast redwood tree to height of the man is 107:3. The difference between the height of the coast redwood tree and the man is 312 ft.

This is what we corrected in class on tuesday!